BlroomDancer Veteran 218 Posts user info edit post |
Is anyone in CHem 201 with Warren? Some reason I cant get the last problem that I ve been working on for ages!!! its # 6 in the webassign due tonight!..It's :
What volume (to the nearest 0.1 mL) of 4.80-M HCl must be added to 0.350 L of 0.300-M K2HPO4 to prepare a pH = 8.00 buffer?
I set up rxn table H3O+HPO4-->H20+H2PO4..........then I used the pH=pKa*log (base/acid) formula. So I got 6.16595=.105-x/4.8*x.......then solved for x and got 3.43 or 34.3. Can anyone tell me what Im doing wrong???? ASAP! Please! Thanks!
3/24/2006 9:07:15 PM |
occamsrezr All American 6985 Posts user info edit post |
See this is why I dropped Warren's class. Motherfucker assigns HW on a friday night. Don't post this shit in the lounge either. 3/24/2006 9:15:30 PM |
CharlieEFH All American 21806 Posts user info edit post |
pH = pKa + log ([base]/[acid]) 3/24/2006 9:16:58 PM |
BlroomDancer Veteran 218 Posts user info edit post |
pH = pKa + log ([base]/[acid])
sorry, this is what I meant..I did it this way but not results! 3/24/2006 9:18:34 PM |
BlroomDancer Veteran 218 Posts user info edit post |
bump 3/24/2006 9:29:38 PM |
spöokyjon ℵ 18617 Posts user info edit post |
I was about to give you the answer
but then you put this shit in the lounge. 3/24/2006 9:44:10 PM |
Raipier Veteran 181 Posts user info edit post |
Yo man im stuck on the same stuff, i cant seem to get 5 or 6. They are set up the same but i cant get it. 3/24/2006 10:02:50 PM |
J_Gatsby All American 1336 Posts user info edit post |
sexy lil' slut you are. 3/24/2006 10:23:59 PM |
Raipier Veteran 181 Posts user info edit post |
What volume (to the nearest 0.1 mL) of 7.20-M NaOH must be added to 0.550 L of 0.200-M HNO2 to prepare a pH = 3.70 buffer?
Can anyone help with this one. 3/24/2006 10:41:53 PM |
damn Suspended 2781 Posts user info edit post |
fuck some chemistry 3/24/2006 11:07:22 PM |
hgtran All American 9855 Posts user info edit post |
it's just the henderson-hasselbach equation. You basically have everything except the concentration of acid. Plug and chug , once you have the concentration, then find the volume since 4.8 M is equal to 4.8 mol/L. 3/25/2006 12:33:54 AM |