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chrissy004
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I need a little help on report 5, I'm not sure how to figure out h. I have q0 = 1, p0=1, q1 = .63, p1 = .37 I am not sure if those numbers are correct; that may be half of my problem.... The equation has h = 1(q1p0/q0-2q0q1); but if p0 =0 than the equation doesn't work. PLEASE HELP!!!

2/27/2007 6:23:17 PM

bamxr4
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i thought you said p0=1 not p0=0?

im not trying to give you the answer b/c i havent even looked at the hmwk yet but im just stating what you posted. If i look at it sometime this week and figure it out i'll get back to you

[Edited on February 27, 2007 at 6:38 PM. Reason : ;]

2/27/2007 6:37:06 PM

chrissy004
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oops i meant p0 = 0, q0 = 1

2/27/2007 6:39:45 PM

chrissy004
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oops i meant p0 = 0, q0 = 1, (though Im not sure that is right), thanks for looking at it though...I have lab tomorrow so I will have to figure it out sometime tonight or go to office hrs tomorrow.

2/27/2007 6:40:42 PM

Joie
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If I'm not mistaken, I believe Dr. Gardner told us to assume that the initial p and q would both be .5 . With would actually make sense phenotypically if all you saw were the stubble flies (since it's dominant AND the recessive lethal).

I hope this is right though, I'm pretty sure she said that, but I would hate to be wrong and mess you up.

[Edited on February 27, 2007 at 9:32 PM. Reason : ahhhh, i have a long night ahead of me ]

2/27/2007 9:32:03 PM

treznor
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Good luck...I freakin loved this class but I will not attempt to help because it has been awhile since I took it and I wouldn't wanna make it wrong for ya!

2/27/2007 11:03:46 PM

chrissy004
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thanks...I think you are right about the .5 for both at the start...I did the practice problem and it worked that way. For the G1 population you just do number of that type divided by total right....nothing different because it is part of a recessive lethal group?

2/27/2007 11:03:59 PM

Joie
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ok, i hope this i sright

if you are talking about the q1, then you have to remember that the stubble allele flies are NOT sb/sb, they are sb/+. so if you want to calculate the allele frenquency of sb (q1), you can't do the total "# of stubble bristle flies" divided by the total number of flies that you counted. If you do that you are also counting the "+" allele. (If they are "stubbly" then their genotype is sb/+; so hypothetically if you counted 4 stubble flies, then you have 8 alleles-4"sb" and 4 "+".)

I hope this helps, its really clumbsy wording

[Edited on February 27, 2007 at 11:27 PM. Reason : ps-what lab are you in?]

2/27/2007 11:27:01 PM

Joie
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hell, i hope thats right

2/27/2007 11:30:45 PM

chrissy004
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yea i know it is late...still not getting it. if i have 63 stubble flies, 37 wilds for 100 total, then i would have 126 stubble alleles...but then what
PS. im in Wed 12:25 lab

2/27/2007 11:36:48 PM

Joie
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^thats my lab too, i sit in the far corner table (i'm the only one without a partner)

ok, you mgiht want to make sure this is right with Dr. Gardner before you take my word for it...

stubble flies have the genotype sb/+ , because the sb is dominant and you cannot have sb/sb flies because they all die.....
you have 63 stubble flies....that means 63 of your flies have sb/+, that's 63 'sb' alleles and 63 '+' alleles
the wild types are (by default) the genotype +/+
you have 37 wild types meaning that you have 74 '+' alleles (since it's homozygous it's 37 +37)

so the total number of alleles should be 63("sb" alleles)+63("+" alleles)+74("+" alleles)
so the # of stubble alleles / total alleles = q1

ok, that's a redundant step-by-step version, but it's the only way I can describe it

[Edited on February 27, 2007 at 11:53 PM. Reason : and i'll be up for another 3 or so hours, i have a horrible day tomorrow ]

[Edited on February 27, 2007 at 11:54 PM. Reason : gah, maybe this studying is getting counterproductive ]

2/27/2007 11:53:29 PM

chrissy004
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thanks so much!!! i dont know why, i just couldn't get that...it has been a busy week. If you ever want to join me and my partner we sit in the back left. Good luck with you busy day tomorrow!!!

2/28/2007 12:09:27 AM

Joie
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no prob

see ya tomorrow

[Edited on February 28, 2007 at 12:14 AM. Reason : ]

2/28/2007 12:13:08 AM

DeeDee21
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joie's explanation works out exactly the same as if you did (#stubble flies)/(2*total flies).

2/28/2007 4:55:48 AM

Joie
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^yeah

i wanted to expalin what was happening though instead of giving the answer.......(midterm's next week )

3/1/2007 7:46:27 AM

bamxr4
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so for a-k on the second page of Report 4 where do we find these answers? the chemicals responsible for each action

3/1/2007 3:34:20 PM

chrissy004
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some are in the course notes, some mentioned in class....but if you search GN 412 in this section (study hall) some of the answers are posted in another thread

3/1/2007 6:39:24 PM

joe_schmoe
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ever find a cabnit?

3/4/2007 3:32:36 AM

deez29
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hahaha that class sucks

3/6/2007 11:26:01 PM

Probasesteal
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anybody ready for the practical?

3/12/2007 8:07:47 PM

PackMan92
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i'm just starting to study now and mine is at 10:15 tomorrow morning...I don't think it'll be that bad and I'm seriously starting to lack motivation for this class

[Edited on March 12, 2007 at 9:20 PM. Reason : ]

3/12/2007 9:19:57 PM

Probasesteal
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mine is at 1:30, heard from a couple people last year it is harder than you think

3/12/2007 9:42:14 PM

chrissy004
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let us know how it goes....mine is on wed

[Edited on March 13, 2007 at 7:42 AM. Reason : GOOD LUCK!!!!]

3/13/2007 7:42:06 AM

arielchic6
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I'm having some trouble with report 6...does anyone know how to figure out the genotype? and whether its linked or not? nothing seems right...thanks!

3/13/2007 3:41:18 PM

PackMan92
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3 mins per station is def. not enough time for some of them

it's not even enough time to write down info to use at the end of class

3/13/2007 3:56:07 PM

Joie
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^someone else told me it wasnt that hard at all


man, i was starting to get a little happy (mines at 12:25 tomorrow and i havent started studying yet)

3/13/2007 6:52:01 PM

chrissy004
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hey, are all the traits x-linked since they are different in the second cross for the male?

3/13/2007 9:08:39 PM

Joie
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thats what i got....

3/13/2007 9:33:47 PM

chrissy004
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well when you do the chi square tests it shows that eye loci segregates randomly..... yet all traits are linked

3/13/2007 10:03:32 PM

bamxr4
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so everything is x-linked and there is nothing autosomal?

3/14/2007 6:05:20 PM

bamxr4
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our class data is totally fucked.....doing the chi-square test with the eyes comes out to 7 which is a reject hypothesis. i think our class has really bad data

3/16/2007 2:15:50 AM

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