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 Message Boards » » someone solve this for me, plz Page [1]  
wdprice3
BinaryBuffonary
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apparently, I don't remember natural log rules too well and can't solve this in a way to produce the correct answer

Q1/Q2 = (1/(LN(R/r1)))/(1/(LN(R/r2))) solve for r2

where 1 and 2 are variable descriptors, and not mathematical operations.

plz

11/4/2008 4:51:57 PM

NCSUGimp
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im not doing your homework faggot

go to class

11/4/2008 4:52:23 PM

FriendlyFire
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i got this...

the answer is eleventy threeve

11/4/2008 4:52:25 PM

BIGcementpon
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schfifty-five

11/4/2008 4:52:47 PM

wdprice3
BinaryBuffonary
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^thanks
^^thanks
^^^too bad this isn't a math class where they teach this shit

[Edited on November 4, 2008 at 4:52 PM. Reason : .]

11/4/2008 4:52:49 PM

GoldenGirl
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i suck at math but my guess is r2=1/r1

11/4/2008 4:53:38 PM

skeeter
IDFWY
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its about three fiddy

11/4/2008 4:53:41 PM

djeternal
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Study Hall
discuss teachers, classes, homework, tests, etc.

11/4/2008 4:56:42 PM

wdprice3
BinaryBuffonary
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if I wanted an answer three days from now...

I GET IT

CC is no longer FF#2
FF is no longer CC#2
CC is no longer TSB #2
etc
etc
etc

[Edited on November 4, 2008 at 4:57 PM. Reason : .]

11/4/2008 4:57:05 PM

IMStoned420
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I'll tell you the answer if you vote for Obama.

11/4/2008 4:57:34 PM

wdprice3
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shit, I voted back in september or early october

11/4/2008 4:57:57 PM

BigEgo
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(e^(Q1/Q2))/r1?

[Edited on November 4, 2008 at 5:02 PM. Reason : k]

11/4/2008 5:01:57 PM

wdprice3
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^n

11/4/2008 5:03:36 PM

BigEgo
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idk then off the top of my head

11/4/2008 5:05:15 PM

parsonsb
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i got r2 equal to exp((Q1(ln(R)-ln(r1))/Q2)+ln(R))

11/4/2008 5:06:27 PM

fjjackso
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go buy a ti-89 titanium

11/4/2008 5:07:10 PM

wdprice3
BinaryBuffonary
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^got an 89, and I can solve it on there. but that's not by hand
^^i'll try it.

I think I may have a solution as well

11/4/2008 5:08:26 PM

BIGcementpon
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http://vcl.ncsu.edu/
Maple or MATLAB

11/4/2008 5:08:39 PM

SaabTurbo
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WHAT'S UP WITH THE CAPITALIZED ln(x)? IS THAT SOMETHING OTHER THAN THE NATURAL LOG? IS IT JUST A COINCIDENCE THAT TWO VARIABLES ARE NAMED L AND N AND HAPPEN TO BE NEXT TO EACHOTHER SON?

11/4/2008 5:10:47 PM

BigEgo
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letting Q1/Q2 = Q for the sake for saving time

Q= ln(R/r2)/ln(R/r1)
Q*ln(R/r1)=ln(R/r2)
Q*ln(R/r1)=ln(R)-ln(r2)
ln(r2)=ln(R)-Q*ln(R/r1)
r2=e^(ln(R)-Q*ln(R/r1))

11/4/2008 5:11:07 PM

wdprice3
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^^used to excel, everything's in capitols


^yep, almost exactly what I just came up with


BIGEGO WINS!!!!!

You get to choose any beer in my fridge and drink it

[Edited on November 4, 2008 at 5:13 PM. Reason : .]

11/4/2008 5:12:51 PM

BigEgo
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there's probably another way to rewrite it but i gotta pee and get ready for 15 minutes or so of class

SWEET!

[Edited on November 4, 2008 at 5:14 PM. Reason : my math skills are legit when i write shit down haha]

11/4/2008 5:14:02 PM

wdprice3
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lol, thanks. there is. both work though. thanks, brah

[Edited on November 4, 2008 at 5:18 PM. Reason : l]

11/4/2008 5:14:34 PM

strudle66
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11/4/2008 5:14:34 PM

BigEgo
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no prob

11/4/2008 5:15:47 PM

0EPII1
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Why did you give the question in such a complicated way? You DO know that, for example, (1/a)/(1/b) = b/a, don't you? So, Q1/Q2 = (1/(LN(R/r1)))/(1/(LN(R/r2))) could be written much simply as

Q1/Q2 = (LN(R/r2))/(LN(R/r1))

Anyway,

Quote :
"r2=e^(ln(R)-Q*ln(R/r1))"


is correct, but FAAAAAAAAAAR from being in simplified form.

That can be simplified to

R^(1-Q) * r1^Q, where Q = Q1/Q2

11/4/2008 6:14:03 PM

 Message Boards » Chit Chat » someone solve this for me, plz Page [1]  
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