User not logged in - login - register
Home Calendar Books School Tool Photo Gallery Message Boards Users Statistics Advertise Site Info
go to bottom | |
 Message Boards » » ridiculously stupid probability question. Page [1]  
joe_schmoe
All American
18758 Posts
user info
edit post

so i've got two normal dice. to roll a 7 is a 16.67% chance.

what if i roll them 4 times? is the overall chance of getting a 7 just 16.67% * 4 = 66.67% chance? doesn't seem right, because using that logic, then rolling them 6 times is a 100% chance.

excuse my ignorance. i got a C in ST370, and that was like 8 years ago.

2/15/2010 2:50:29 AM

johnny57
All American
624 Posts
user info
edit post

oh wow

2/15/2010 3:48:52 AM

DPK
All American
2390 Posts
user info
edit post

Ignoring the law of averages or other crazy number theories, your odds are still the same for every roll of a set of dice.

2/15/2010 5:43:46 AM

EuroTitToss
All American
4790 Posts
user info
edit post

I want to say 1-(1-p)^n

but it's been like 5 years since I took statistics

in other words, getting a 7 within two rolls is the chance of getting it once plus the chance of NOT getting it once and getting it the second time. maybe

[Edited on February 15, 2010 at 7:32 AM. Reason : asdf]

2/15/2010 7:31:07 AM

jethromoore
All American
2529 Posts
user info
edit post

16.67%^4= .077% (1 in 1300 chance to roll 4 7's in a row)

^I think that's right if you are looking for the chance of getting atleast one 7 in 4 rolls

[Edited on February 15, 2010 at 8:35 AM. Reason : ]

2/15/2010 8:34:13 AM

0EPII1
All American
42541 Posts
user info
edit post

Quote :
"what if i roll them 4 times? is the overall chance of getting a 7"


question is ambiguous.

you will roll 2 dice, and then repeat this 3 more times, right?

what do you want the probability of? a sum of 7 each of the 4 times? a sum of 7 at least once?

4 times: (1/6)^4 = 1/1,296

at least once: 1 - (prob of not a sum of 7 in 4 repetitions) = 1 - (5/6)^4 = 671/1,296

2/15/2010 8:54:00 AM

neolithic
All American
706 Posts
user info
edit post

^Is correct.

Phrasing on this is pretty ambiguous.

[Edited on February 15, 2010 at 2:10 PM. Reason : ]

2/15/2010 2:09:01 PM

qntmfred
retired
40723 Posts
user info
edit post

but what if you roll 8 dice, 1 at a time?

2/16/2010 8:55:30 PM

EuroTitToss
All American
4790 Posts
user info
edit post

what I want to know is how you get a 7 on normal dice

2/16/2010 10:35:03 PM

neolithic
All American
706 Posts
user info
edit post

Dice = 2 die. 3+4 = 7 or 5+2=7 or 6+1=7

2/16/2010 11:07:58 PM

EuroTitToss
All American
4790 Posts
user info
edit post

jesus christ, I'm illiterate

2/17/2010 6:44:00 AM

Colemania
All American
1081 Posts
user info
edit post

.1667^4 = 0.0772222% chance of it happening

Assuming that the previous rolls probability doesnt alter your current probability on your next roll.

A more simple example: Youre an 80% free throw shooter, chances of making two in a row are:
.8^2 = 64%, assuming that making the first doesnt increase or decrease the odds of making the next one.

2/22/2010 3:15:06 PM

neolithic
All American
706 Posts
user info
edit post

^ The OP didn't say whether it was for seeing one 7 or four sevens in a row.

2/22/2010 5:48:07 PM

EuroTitToss
All American
4790 Posts
user info
edit post

kind of ridiculous that we're arguing over the OP's intentions as if he were one of the founding fathers or some shit, but...

Quote :
"the overall chance of getting a 7"


seems like he meant at least one 7 to me, not all 7s

2/22/2010 6:38:15 PM

0EPII1
All American
42541 Posts
user info
edit post

Quote :
"kind of ridiculous that we're arguing over the OP's intentions as if he were one of the founding fathers or some shit, but..."


^ Huh? You are being weird... we are arguing over it because it really is not clear what he meant (as he used non-standard language), and he is the one who needs the answer. What's ridiculous about that?

And if you really want to guess from his non-standard language ("the overall chance of getting a 7"), I don't see how you can construe "a 7" to mean "at least one 7" if you are taking it literally.

To recap:

One 7: 4*(1/6)*(5/6)^3 = 500/1,296 ~ 39%

>= One 7: 1 - (5/6)^4 = 671/1,296 ~ 52%

All 7s: (1/6)^4 = 1/1,296 ~ 0.077%

But yeah, we really are the idiots for arguing over this... joe_schmoe posted his question and disappeared. He needs to show up and explain what he meant .


[Edited on February 23, 2010 at 6:31 AM. Reason : ]

2/23/2010 6:21:54 AM

EuroTitToss
All American
4790 Posts
user info
edit post

the OP probably stopped giving a fuck a week ago

but we're still debating his confusion like it's holy scripture or the constitution

2/23/2010 9:27:39 AM

neolithic
All American
706 Posts
user info
edit post

It turns out this thread was very appropriately titled.

2/23/2010 1:49:02 PM

Firehoze
New Recruit
5 Posts
user info
edit post

Visit http://www.firehoze.com for help with Probabilities, lessons are organized into a searchable catalog and you can also engage in online discussion with instructors and other students.

Lessons explaining probability and statistics ([i]with examples) can be found here:

http://www.firehoze.com/categories/statistics%20&%20probability

The site is currently in development phase and is building a base of very helpful lessons and topics. Firehoze also presents a good opportunity for students as well. Once becoming an instructor and uploading a lesson on a topic of your choice, you have the opportunity to receive royalties each time your lesson is purchased. There is no commitment to teaching lessons and plenty of opportunity!

3/3/2010 10:30:05 AM

EuroTitToss
All American
4790 Posts
user info
edit post

BUY

AN

AD

3/3/2010 8:59:19 PM

joe_schmoe
All American
18758 Posts
user info
edit post

lol.... sorry. i forgot all about this thread. i think i was half-drunk playing Settlers of Catan online. and as for my "original intent", i was trying to ask

-- what is the probability that I will *eventually* get a 7, when rolling two dice, 'n' number of times ?

IOW, a score of 7 has a 16.66% chance of occurring on any given roll of these two dice. if i roll these two dice 4 times, what's the probability that at least one of those throws will result in a score of 7.

3/16/2010 12:35:52 PM

 Message Boards » Study Hall » ridiculously stupid probability question. Page [1]  
go to top | |
Admin Options : move topic | lock topic

© 2024 by The Wolf Web - All Rights Reserved.
The material located at this site is not endorsed, sponsored or provided by or on behalf of North Carolina State University.
Powered by CrazyWeb v2.39 - our disclaimer.