1...2....2 pagesah..ah..ah...ahhhhh
4/30/2009 2:05:03 PM
4/30/2009 2:05:40 PM
but will the plane take off?[Edited on April 30, 2009 at 2:08 PM. Reason : .]
4/30/2009 2:08:25 PM
only if the answer is -8 m/s
4/30/2009 2:09:38 PM
not only will the plane take off, but to the left and between 0 and 4 seconds of some time interval, the average velocity will be 8 meters-per-secondso then it will crash because its not going fast enough[Edited on April 30, 2009 at 2:10 PM. Reason : LEFT A WORD OUT]
4/30/2009 2:09:52 PM
4/30/2009 2:53:24 PM
4/30/2009 2:54:52 PM
i got -8 m/s, am i an idiot[Edited on April 30, 2009 at 2:59 PM. Reason : /]
4/30/2009 2:58:52 PM
4/30/2009 2:59:47 PM
average velocity is the distance traveled divided by the time, you don't need calculus to solve this
4/30/2009 3:03:02 PM
leave it to wolfwebbers to adamantly insistent that an incorrect approach is right, and that a correct approach is wrong, because they fail at reading.Though to be fair, it's probably just the chit-chat factor. Posting this thread in Study Hall means it would never make it to two pages, but it would probably have a higher proportion of correct answers.[Edited on April 30, 2009 at 3:26 PM. Reason : ]
4/30/2009 3:21:47 PM
4/30/2009 3:44:42 PM
plane.....treadmill.....flight....no
4/30/2009 5:37:16 PM
4/30/2009 6:08:26 PM
is velocity directional?because x is obviously directionalbut should velocity be considered positive or negative?
4/30/2009 6:53:42 PM
velocity is a vectorspeed is a scalar
4/30/2009 6:56:54 PM
it just means it's going in the negative direction right
4/30/2009 6:57:08 PM
yes
4/30/2009 6:57:25 PM
I just found out teh velocity at diff times i.e V@0,1,2,3,4 secs and took the avg. there are simpler ways of doing it.. but u'll still get -8m/s
4/30/2009 7:00:17 PM
wow to the first page
4/30/2009 7:16:16 PM
its -8, it would be -11 if it where from 1 to 4 though, did it say the velocity at t=0?
4/30/2009 7:24:41 PM
this has been bothering me all day, someone confirm -8 m/s so i can stop feelin like an idiot
4/30/2009 7:25:27 PM
It's possible for the final to be wrong. On my physics final, I think 2 problems had bad answers, and the questions had to be thrown out. This wasn't determined until after the test was over though.
4/30/2009 7:30:24 PM
Looks like -8 m/s to me, but I'm not an applied physicist either.ibt42
4/30/2009 7:45:49 PM
You can do it from the position function (change in distance over change in time) and you do it by differentiating it.Either way, the answer is -8 m/s.
4/30/2009 7:58:45 PM
I also calculated -8What is your professor's name? We should all email him.
4/30/2009 8:01:31 PM
Yes it did say starting from t = 0. Interesting that it works at t =1 . I wonder if it's a typo, either way, I've emailed him this morning. No response yet.
4/30/2009 9:59:31 PM
at t(0) you are at 0 mat t(1) you are at 1 mat t(2) you are at -4 mat t(3) you are at -25 mat t(4) you are at -32 mso I don't think you can just do -32/4 = -8 because you actually went further than 32 m?[Edited on April 30, 2009 at 10:18 PM. Reason : missed a -]
4/30/2009 10:13:29 PM
huh? how did you go further than 32 m?you went from 0 m to -32 m in 4 seconds.average velocity is -32/4 m/s.
4/30/2009 10:15:53 PM
^^you determine average velocity by net displacement[Edited on April 30, 2009 at 10:17 PM. Reason : .]
4/30/2009 10:17:10 PM
^^ you went from 0 to (at least) 1 before going negative its like if i drove 1 mile N and then 33 meters S I went from 0 to -32 but i drove more than 32 meters
4/30/2009 10:21:48 PM
all that matters is the NET displacement[Edited on April 30, 2009 at 10:22 PM. Reason : final minus initial motherfucker][Edited on April 30, 2009 at 10:23 PM. Reason : vector vs. scalar]
4/30/2009 10:22:34 PM
VELOCITYnot SPEED
4/30/2009 10:25:08 PM
the answer is faraday
4/30/2009 10:27:53 PM
4/30/2009 10:36:35 PM
answer is DP/DT
4/30/2009 10:39:18 PM
5/2/2009 4:48:55 PM
yea drod just got avg position, which doesnt tell you anything
5/2/2009 5:55:55 PM
Oops, forgot to say that ^^ was what the prof. emailed back.
5/2/2009 5:57:39 PM