User not logged in - login - register
Home Calendar Books School Tool Photo Gallery Message Boards Users Statistics Advertise Site Info
go to bottom | |
 Message Boards » » math problem Page [1]  
wolftrap
All American
1260 Posts
user info
edit post

develop an equation that will produce the following result for y given x and some constant c (in this case 3)
c=3
x y
0 -3
1 -2
2 -1
3 1
4 2
5 3

no this isn't for a class
I have been out of school for a long time

9/29/2005 2:12:16 PM

Aficionado
Suspended
22518 Posts
user info
edit post

y = x -3

but that really doesnt work unless you have a number that corresponds to 0

so i dont really know

9/29/2005 2:14:39 PM

Ernie
All American
45943 Posts
user info
edit post

this makes no sense

9/29/2005 2:16:32 PM

Excoriator
Suspended
10214 Posts
user info
edit post

haha i was gonna be a smartass and give you a piece-wise eqn

but then i got too lazy to even do that

9/29/2005 2:20:58 PM

psnarula
All American
1540 Posts
user info
edit post

i can give you a polynomial f(x) such that f(0) = -3, f(1) = -2, f(2) = -1, f(3) = 1, f(4) = 2, and f(5) = 3 but i don't understand where the constant c comes into play...

[Edited on September 29, 2005 at 3:03 PM. Reason : asdf]

9/29/2005 2:53:12 PM

Excoriator
Suspended
10214 Posts
user info
edit post

just throw on a constant of -3 added to c to the end of the polynomial

that'll take care of 'c'

[Edited on September 29, 2005 at 3:34 PM. Reason : s]

9/29/2005 3:33:51 PM

psnarula
All American
1540 Posts
user info
edit post

f(x) = (1/20 * x^5) - (5/8 * x^4) + (8/3 * x^3) - (35/8 * x^2) + (197/60 * x) - 3

now what does the constant c have to do with anything?

9/29/2005 3:33:54 PM

Excoriator
Suspended
10214 Posts
user info
edit post

f(x) = (1/20 * x^5) - (5/8 * x^4) + (8/3 * x^3) - (35/8 * x^2) + (197/60 * x) - 3 + c


thar ya go

9/29/2005 3:34:34 PM

qntmfred
retired
40810 Posts
user info
edit post

way to subtract, no-subtract

9/29/2005 5:28:53 PM

Excoriator
Suspended
10214 Posts
user info
edit post

math sarcasm is obviously beyond your comprehension

9/29/2005 6:47:53 PM

psnarula
All American
1540 Posts
user info
edit post

by the way -- the method used to solve problems like this is called "finite differences". if you google for it you'll find lots of nice tutorials and examples.

recall that two different points uniquely determine a polynomial of degree one (ie, a line). similarly, it is the case that n different points uniquely determine a polynomial of degree n-1. so given any six unique points, there is always a unique 5th degree polynomial that passes through them.

9/29/2005 9:15:13 PM

virga
All American
2019 Posts
user info
edit post

least squares is good, too.

9/29/2005 9:24:37 PM

Incognegro
Suspended
4172 Posts
user info
edit post

you know, I'm just going to have to warn you that, while I don't know what you're using this for, this probably isn't the best way to go about doing it

9/30/2005 1:09:28 PM

TypeA
Suspended
3327 Posts
user info
edit post

Would noen know the best way to go about it?

9/30/2005 1:25:16 PM

SandSanta
All American
22435 Posts
user info
edit post

lol

9/30/2005 1:25:57 PM

Incognegro
Suspended
4172 Posts
user info
edit post

would... your mother? oooo

9/30/2005 4:07:21 PM

afripino
All American
11433 Posts
user info
edit post



[Edited on October 1, 2005 at 12:32 PM. Reason : ooooo]

10/1/2005 12:32:16 PM

 Message Boards » Tech Talk » math problem Page [1]  
go to top | |
Admin Options : move topic | lock topic

© 2024 by The Wolf Web - All Rights Reserved.
The material located at this site is not endorsed, sponsored or provided by or on behalf of North Carolina State University.
Powered by CrazyWeb v2.39 - our disclaimer.