virga All American 2019 Posts user info edit post |
Hey -- if anyone out there in TWW land are also working on this problem, but I'll throw it out.
Well, two questions I guess. First is Prove that a factor group of a cyclic group is cyclic. Obviously I know what a cyclic group is, but I don't know how to incorporate that into the factor group.
The second question is what is the order of 14 + <8> in the factor group Z_24 / <8>. I know that Z_24 / <8> becomes ... Z_6 (?), but I'm not sure how.
Thanks for any help you can throw my way.. 4/2/2006 2:33:30 PM |
mathman All American 1631 Posts user info edit post |
^ yep. Like he said remember that for a cyclic group we know how to explicitly write each and every element in terms of the generator raised to some power (0,1,2,3,...,g -1). For a cyclic group G of order g we knows:
G = {e,a,a^2,a^3,...A^g-1} with a^g=e
or if you like,
G = {0,a,2a,3a,...(g-1)a} with ga= 0
I suppose you'll want to think about additive groups in view of the problem to follow.
[Edited on April 2, 2006 at 4:42 PM. Reason : formatting] 4/2/2006 4:41:16 PM |