So I need help with this. I'm trying to create a program where the user selects the basic math functions(+, - , *, /). That part is fine but how would I go about lets say if the user selects the random option where it can pick from any of those four?

10/5/2007 2:42:49 PM

what?

10/5/2007 2:57:53 PM

add a ; to the end of each line.

10/5/2007 2:59:14 PM

enumerate the math types and call the random function in the standard library:

double RandomMath(double num1, double num2)
{
	enum myMathCrap { ADD = 0, SUBTRACT = 1, MULTIPLY= 2, DIVIDE = 3 };

	int iRandomInteger = rand()%4;  // This gives you a random number between 0 and 3

	double result = 0;
	switch (iRandomInteger)
	{
		case ADD:
			result = num1 + num2;
			break;
		case SUBTRACT:
			result = num1 - num2;
			break;
		case MULTIPLY:
			result = num1 * num2;
			break;
		case DIVIDE:
			result = num1 / num2;
			break;
	}
	return result;
}

10/5/2007 3:22:05 PM

^why are you gonna do this guy's homework for him?

10/5/2007 3:35:09 PM

What language?

10/5/2007 3:46:07 PM

I'm not being graded on this. Just wanted to know how to do it. The language is in c++. thanks for the help.

10/5/2007 3:54:36 PM

Curious, I couldn't put a switch statement within another switch statement correct? I would prob have to use if/else.

10/5/2007 5:12:44 PM

i dont see why you couldnt though ive never tried it.

10/5/2007 7:33:40 PM

As long as you surround the nested switch statement in each case with brackets then it should be fine:

switch (num)
{
	case 0:
	{
		switch (num2)
		{
			case 0:
				// do stuff
				break;
			case 1:
				// do other stuff
				break;
			default:
				break;
		}
	}
	case 1:
	{
		switch (num2)
		{
			case 0:
				// do crazy stuff
				break;
			case 1:
				// do more crazy stuff
				break;
			default:
				break;
		}
	}
	case 2:
		// do normal stuff
		break;
	default:
		break;
}

10/5/2007 10:35:33 PM

you can put most any constructs within a switch block, as Duff's device demonstrated.

 switch (count % 8)  /* count > 0 assumed */
 {
   case 0:        do {  *to = *from++;
   case 7:              *to = *from++;
   case 6:              *to = *from++;
   case 5:              *to = *from++;
   case 4:              *to = *from++;
   case 3:              *to = *from++;
   case 2:              *to = *from++;
   case 1:              *to = *from++;
                     } while ((count -= 8) > 0);
 }

10/6/2007 12:59:40 AM