It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This insect can accelerate at 4100 m/s2 over a distance of 1.7 mm as it straightens its specially designed "jumping legs."
(a) Assuming a uniform acceleration, what is the velocity of the insect after it has accelerated through this short distance, and how long did it take to reach that velocity?
velocity: ??m/s
elapsed time: ??ms

I got these^^3.73363m/s and .9106ms.... but how do i get the next one?

(b) How high would the insect jump if air resistance could be ignored? Note that the actual height obtained is about 0.7 m, so air resistance is important here.
m

9/1/2009 10:48:47 PM

holy fucking google

http://www.google.com/search?q=%22Assuming+a+uniform+acceleration%2C+what+is+the+velocity+of+the+insect+after+it+has+accelerated+through+this+short+distance%2C+and+how+long+did+it+take+to+reach+that+velocity%3F&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a

9/1/2009 10:54:13 PM

All you need to know is that it turns work into potential energy... or you can blindly use a kinematic equation because it just works somehow.

9/2/2009 3:28:36 PM

cramster.com has all the answers. that was probably the best place for physics and chem webassigns until they changed the search function so that it's completely broken.

9/2/2009 7:05:21 PM

Calculus FTW!

Acceleration = X
Velocity = Xt + V0 (integration of acceleration over time)
Position = 0.5tX^2 + V0t + P0 (integration of velocity over time)

X = constant acceleration value
t = time
V0 = initial velocity
P0 = initial position

9/11/2009 12:54:21 AM